Solving a Static and Kinetic Friction Problem

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SUMMARY

The discussion focuses on solving a physics problem involving static and kinetic friction with two masses, m1 (10 kg) and m2 (4 kg). The coefficient of static friction is 0.50, while the coefficient of kinetic friction is 0.30. The key equations used include Fnet = ma, which is essential for calculating the acceleration of the system. The problem requires understanding the distinction between static and kinetic friction to determine the forces acting on both boxes.

PREREQUISITES
  • Understanding of Newton's Second Law (Fnet = ma)
  • Knowledge of static and kinetic friction coefficients
  • Basic principles of pulley systems in mechanics
  • Ability to analyze forces acting on multiple bodies
NEXT STEPS
  • Study the application of Newton's Second Law in multi-body systems
  • Learn how to calculate frictional forces using static and kinetic coefficients
  • Explore the dynamics of pulley systems in physics
  • Practice problems involving multiple masses and friction
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of static and kinetic friction applications in problem-solving.

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Homework Statement


In the following figure(one box on a table, m1, connected to a string that is on a pulley attached to box m2), m1=10kg and m2=4kg. The coefficient of static friction between m1 and the horizonatl surface is 0.50 while the coefficient of kinetic friction is 0.30. (a) If the system is released from rest, what will its acceleration be? (b) If the system is set in motion with m2 moving downward, what will be the acceleration of the system?


Homework Equations


Fnet=ma


The Attempt at a Solution


I've only done problems with a single friction or coefficient of friction given and I don't understand how to use kinetic or static. I've never worked with them before so I have no idea on how to go about this.
 
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The static coefficient is used to calculate the force of friction when there is no motion, if things are moving you use the kinetic coefficient to calculate friction. For part (a) what are all the forces on the two boxes?
 

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