mistereko
- 25
- 0
Homework Statement
How do I get y'' - yω2 = y'(sinωx + sinhωx) + y(cosωx*ω + coshωx*ω)
equal to
y'' - yω2 = sinωx + sinhωx
I'm baffled.
The discussion centers on the differential equation y'' - yω² = y'(sinωx + sinhωx) + y(cosωx*ω + coshωx*ω). Participants express confusion regarding the simplification of this equation to y'' - yω² = sinωx + sinhωx. The consensus is that the right-hand side resembles the differentiation of a product of two functions, indicating that direct equality may not be achievable without further manipulation or specific conditions.
PREREQUISITESStudents studying differential equations, mathematicians tackling complex equations, and educators seeking to clarify concepts related to trigonometric and hyperbolic functions in mathematical contexts.