Solving Fx for 50kg Skier Down Hill

[1MileCrash]

Homework Statement

A 50kg skier skis directly down a frictionless slope angled 16* to the horizontal. Assume the skier moves at a negative x direction. A wind force with component Fx acts on the skier.

What is Fx if the skier's velocity magnitude is constant?

Homework Equations

The Attempt at a Solution

I really have no idea. I assume Fx is equal to the force the skier exerts "on the air" so F = ma on the skier.

But I am utterly confused when they say velocity is constant. He is going down the slope due to gravity, how could his velocity be constant? It makes no sense to me.

 

[Spinnor]

The negative x direction is the direction the skier goes. There are two forces which act in the x direction on the skier, -sin(16)*m*g and F_x, they are equal and opposite.

 

[1MileCrash]

How would I adjust that if the skier's velocity is increasing 10m/s/s?

-sin(16)(5)(9.8 + 10t)
?