Force and Motion: Skier's Fx for V Constant, Increasing 1.5 m/s2, 3.0 m/s

[dortec]

A 53 kg skier skis directly down a frictionless slope angled at 15° to the horizontal. Choose the positive direction of the x-axis to be downhill along the slope. A wind force with component Fx acts on the skier. What is Fx if the magnitude of the skier's velocity is (a) constant, (b) increasing at a rate of 1.5 m/s2, and (c) increasing at a rate of 3.0 m/s.

 

[the pro]

give us the atempt at the sulution then we can try to help u

 

[dortec]

i did it and got
a: 137.17 n
b: 57.5 n
c: -22n

but I am pretty sure they're wrong:P

 

[the pro]

with which formula

did u do this with the one of potencial energy

 

[dortec]

sigma Fext= M.a Newton's second law i think:P .. and u place the forces.. that's how i did it.

 

[the pro]

so u did this with the second law of Newton f=m x a

 

[dortec]

yes|-) .. now can someone help me please^o)?

 

[Jebus_Chris]

There are two forces, the force of the wind and his weight (only in the c-direction, down the ramp).

a) Constant velocity means that there is no acceleration and the net force is zero.

b/c) He is accelerating down the hill which means that there is a net force.

Draw an fbd then you can create an equation for a/b/c based on the parameters.

 

[the pro]

u did just the forces but how about the angel that's ur failur a

 

[the pro]

There are two forces, the force of the wind and his weight.

a) Constant velocity means that there is no acceleration and the net force is zero.

b/c) He is accelerating down the hill which means that there is a net force.

Draw an fbd then you can create an equation for a/b/c based on the parameters.

nah he did that with the f=ma parameters but u need to put the angel so if it is like u say it will go like this f=ma=53kg x o m/s² and then he would have o N and u would do 2 and 3 like this