Solving gradients of right angle triangle

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SUMMARY

The discussion focuses on calculating the gradient of a right-angle triangle, specifically how to derive the value of m3. The formula m3 = (hz + delta_hz) / u1 is established, leading to the rearrangement u1 = (hz + delta_hz) / m3. The critical equation m3 = 1/k3 + k3 is questioned, with participants seeking clarification on its derivation. The conversation emphasizes the importance of defining the lengths of the triangle's sides to accurately determine gradients.

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mamort
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Please take a look at attached diagram displaying gradients of each line, please explain how m3 is obtained.
Gradient Problem.jpg
 
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No. If you don't specify how long the arms of the short sides of the right triangle need to be, then you can make m3 be whatever you want, and you'll still have a right-triangle with 1/x and -x as the gradient of two of the sides.
 
True I think I might of head down the wrong path I am trying to solve the following problem in the diagram below. I am unsure how u1 is obtained. I assume that the gradient of the green line is used to solve as shown below

m3 = (hz+delta_hz)/(u1)
therefore
u1 = (hz+delta_hz)/m3
where
m3 = 1/k3+k3

If this is the case then how has m3 = 1/k3 + k3 been calculated?
Otherwise can you please explain how u1 has been obtained?
Geometric Problem.jpg
 

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