Solving Gravitational Force: F_g between Ring & Mass m at Distance x

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SUMMARY

The discussion focuses on calculating the gravitational force F_g between a ring and a mass 'm' positioned at a distance 'x' from the ring's center. The user derived the gravitational force using potential energy concepts and integration, arriving at F(d) = (2GmM)/(r² + x²)^(3/2). However, this result differs from the expected answer, F = (GMmx)/(r² + x²)^(3/2), indicating a misunderstanding in the integration process or the application of the work-energy principle.

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Homework Statement



What is the intensity of the force [itex]F_{g}[/itex] between the ring and a mass 'm', which is at a distance 'x' from the center of the ring?

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The Attempt at a Solution



I have got to my own answer, but it is different from the given one. Here's what I did:

There's a potential energy between 'm' and a dM from the ring, which is given by [itex]dU=-G*m*dM/d[/itex] and [itex]d=\sqrt{r^{2}+x^{2}}[/itex].

From this, I can find the total potential energy by integrating dU from 0 to M, which gives me [itex]U=-\int^{M}_{0}\frac{G*m*dM}{d}=\frac{-G*m*M}{\sqrt{r^{2}+x^{2}}}[/itex]

As the variation in the potential energy is equal to the negative of the work done, I did [itex]-\int^{0}_{d}F(d)*dd=\frac{-G*m*M}{\sqrt{r^{2}+x^{2}}}[/itex][itex]\Rightarrow[/itex][itex]F(d)=\frac{2*G*m*M}{(r^{2}+x^{2})^{3/2}}[/itex]

So, what's wrong? Thanks
 
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I think [itex]-\int^{0}_{d}F(d)*dd[/itex] should be [itex][itex]-\int^{0}_{d}F(d)*cos\theta*dd[/itex], but even this way I didn't get the right answer.[/itex]
 
Sorry, forgot to post the given answer for the exercise: [itex]F = \frac{GMmx}{(r^2+x^2)^{3/2}}[/itex]
 

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