Solving Hermitical Operator Homework Questions

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Homework Help Overview

The discussion revolves around solving problems related to Hermitian operators in quantum mechanics, specifically focusing on integrals involving wave functions and their derivatives. Participants are exploring the mathematical formulation and properties of these operators.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster questions whether to simplify the expression or approach it differently, and inquires about the integral of a function over a specified range. Other participants suggest using integration by parts for the integral presented.

Discussion Status

Participants are actively engaging with the problem, with some offering guidance on potential methods such as integration by parts. There is a mix of interpretations regarding the correctness of the results, but no explicit consensus has been reached.

Contextual Notes

There are constraints regarding the range of integration and the specific properties of the functions involved, which are being discussed but not resolved.

Tegalad
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Homework Statement


1.png

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Homework Equations


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2.png

The Attempt at a Solution


Should I do this
3.png
IY4ULEt
or I can just simplify it like this
4.png
QRu7MeC
?
And also what would the integral of f(r) equal to at -inf<r<0?
 
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##\int_{0}^{\infty} \psi^*i\frac{\partial}{\partial r} r^2 \varphi dr##

The range of ##r## is ##0## to ##\infty##. For your first step, you might try an integration by parts.
 
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TSny said:
##\int_{0}^{\infty} \psi^*i\frac{\partial}{\partial r} r^2 \varphi dr##

The range of ##r## is ##0## to ##\infty##. For your first step, you might try an integration by parts.
Thank you very much!
 
TSny said:
##\int_{0}^{\infty} \psi^*i\frac{\partial}{\partial r} r^2 \varphi dr##

The range of ##r## is ##0## to ##\infty##. For your first step, you might try an integration by parts.
I get that the answer is https://imgur.com/OdTtc5D Is it correct?
 
Yes, I think that's correct.
 
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