Solving homogeneous system involving decimal eigenvalues

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SUMMARY

The discussion focuses on solving a homogeneous system involving the matrix [3 5; -1 -2]. The eigenvalues are calculated as λ = 1/2 + (√5)/2 and λ = 1/2 - (√5)/2 using the determinant formula det(A - λI). The next step involves reducing the matrix to find the corresponding eigenvectors. The correct form of the matrix for the first eigenvalue is [5/2 - √5/2, 5; -1, -5/2 - √5/2], which requires row reduction to identify the eigenvector.

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  • Understanding of eigenvalues and eigenvectors
  • Familiarity with matrix operations, specifically row reduction
  • Knowledge of determinants and the characteristic polynomial
  • Proficiency in solving quadratic equations
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  • Learn how to perform row reduction on matrices
  • Study the process of finding eigenvectors from eigenvalues
  • Explore the implications of eigenvalues in system stability analysis
  • Investigate applications of eigenvalues and eigenvectors in differential equations
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Students studying linear algebra, mathematicians working on eigenvalue problems, and anyone involved in systems analysis or differential equations.

maxfails
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Homework Statement



I need to find the general solution of the system
[3 5]
[-1 -2]

Homework Equations



so to get the eigenvalues, det(A - λI)

The Attempt at a Solution



determinant is (3-λ)(-2-λ) + 5

which would be λ2 - λ - 1

so by the quadratic equation the eigenvalues are λ = 1/2 + (√5)/2 and 1/2 - (√5)/2

but now I don't know how to reduce the matrix to get the eigenvectors?

I think the matrix for the first eigenvalue would be
[3-(1/2 + √5)/2) 5]
[-1 -2-1/2+(√5)/2]

What to do now?
 
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maxfails said:

Homework Statement



I need to find the general solution of the system
[3 5]
[-1 -2]

Homework Equations



so to get the eigenvalues, det(A - λI)

The Attempt at a Solution



determinant is (3-λ)(-2-λ) + 5

which would be λ2 - λ - 1

so by the quadratic equation the eigenvalues are λ = 1/2 + (√5)/2 and 1/2 - (√5)/2

but now I don't know how to reduce the matrix to get the eigenvectors?

I think the matrix for the first eigenvalue would be
[3-(1/2 + √5)/2) 5]
[-1 -2-1/2+(√5)/2]

What to do now?
Do what you would normally do - row reduce the matrix, but you'll need to fix some misplaced parentheses first.

The matrix should be
[3- (1/2 + √5/2) 5]
[-1 -2- (1/2+√5/2)]

=

[5/2 - √5/2) 5]
[-1 -5/2 - √5/2]

You had a few too many parentheses in your matrix.

When the matrix is row-reduced, there should be a row of zeroes, and you can use the other row to get your eigenvector.
 

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