Solving Impulse Graph Questions: Velocity Calculation & Solution Check

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Homework Help Overview

The discussion revolves around a physics problem related to impulse and momentum, specifically focusing on calculating the final velocity of an object after a specified time interval of impact. Participants are analyzing a force versus time graph and its implications on the object's motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the interpretation of the problem statement, particularly the meaning of finding the velocity at the end of the impact duration. There are attempts to clarify the relationship between impulse and momentum, with some participants questioning the setup and definitions involved.

Discussion Status

Some participants have provided guidance on interpreting the impulse-momentum theorem and its application to the problem. There is an ongoing exploration of the necessary calculations and the implications of the given information, with multiple interpretations being considered.

Contextual Notes

Participants express uncertainty regarding the net force (fnet) and its role in the calculations. There is also confusion about the specific requirements of the problem, particularly what is meant by the velocity "after" the 1.20 seconds of impact.

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Homework Statement





Homework Equations


fnet(delta t) = m (delta v)


The Attempt at a Solution


I need some help on question b ASAP (i'm not sure what the question means when it says find the velocity AT THE END of the 1.20 sec impact)
and i would like for someone to check if I've answered question A correctly
 

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A looks right.And for part B, the problem seems set up where that graph of F vs. t is the forces acting on the player for 1.2s. It gives you an initial velocity, and asks what those forces (so the impulse that you already calculated) make her final velocity.
 
Nitrate said:

Homework Statement



Homework Equations


fnet(delta t) = m (delta v)

The Attempt at a Solution


I need some help on question b ASAP (i'm not sure what the question means when it says find the velocity AT THE END of the 1.20 sec impact)
and i would like for someone to check if I've answered question A correctly
attachment.php?attachmentid=48101&d=1339036908.png


What does the Impulse - Momentum Theorem say ?
 
SammyS said:
attachment.php?attachmentid=48101&d=1339036908.png


What does the Impulse - Momentum Theorem say ?

not sure
 
The impulse is defined as the integral of a force with respect to time. Wiki "impulse" if you need more help
 
Nitrate said:
not sure
Momentum Theorem is something like:

An object's change in momentum is equal to the net impulse on the object.


Look it up to be sure!
 
i believe I've found the integral in part A but i don't know what part b means by "find the velocity at 1.20 seconds"

i've got the following information compiled for part b)
fnet(delta t) = m (delta v)
delta t = 1.20 seconds
Fnet = ?
m = 60 kg
vi = 7.0 m/s
vf = ?

my problem is that i don't know what fnet is.
 
I=Δp

so you know your initial momentum. Now find the final momentum, using the above fact. :biggrin:
 
Nitrate said:
i've got the following information compiled for part b)
fnet(delta t) = m (delta v)

...

my problem is that i don't know what fnet is.

What's the name for fnet(delta t)?
 
  • #10
Villyer said:
What's the name for fnet(delta t)?

impulse. however, i don't know if i did part A right and i don't know if they want me to use all the information in question B... and i do not understand what they mean by AFTER 1.20 seconds
 
  • #11
Nitrate said:
... and i do not understand what they mean by AFTER 1.20 seconds

Look at the graph again .
 
  • #12
You have an initial momentum - think about how that impulse ( change in momentum) will change the player's speed. (you're looking for pf)
 
  • #13
Nitrate said:
impulse. however, i don't know if i did part A right and i don't know if they want me to use all the information in question B... and i do not understand what they mean by AFTER 1.20 seconds

Your part A was right.

And it just means that at t = 0 the velocity is 7, what is the velocity at t = 1.2?
 
  • #14
i think i got it
-360 n*s = 60(vf-7)
-6=vf-7
vf=1 m/s
?
 
  • #15
correct
 

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