Solving Inelastic Collision for Two Hockey Players | Physics Problem

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SUMMARY

The problem involves two 75 kg hockey players colliding inelastically at a speed of 5.75 m/s with an angle of 125 degrees between their initial directions. The correct approach to solve for their final velocity after the collision is to apply the conservation of momentum principle, represented by the equation m_1\vec{v_1} + m_2\vec{v_2} = (m_1 + m_2)\vec{v_f}. To simplify calculations, it is recommended to define the x-axis along the line bisecting the 125-degree angle, which streamlines the momentum calculations for both x and y components.

PREREQUISITES
  • Understanding of conservation of momentum in physics
  • Ability to resolve vectors into components
  • Familiarity with trigonometric functions (sine and cosine)
  • Basic knowledge of inelastic collisions
NEXT STEPS
  • Study the conservation of momentum in two-dimensional collisions
  • Learn how to resolve vectors into their x and y components
  • Explore the concept of inelastic collisions and their characteristics
  • Practice problems involving angles in collision scenarios
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Physics students, educators, and anyone interested in understanding the principles of momentum and collision dynamics in two-dimensional scenarios.

Huskies213
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Can anyone tell me what i am doing wrong for this problem?
Two 75 kg hockey players skating at 5.75 m.s collide and stick together. If the angle btween their initial directions was 125 degrees, what is their velocity after the collision?

I used the formula Vf = m1v1/(m1+m2) cos 125 for the x value which is supposed to come out to be 1.23 m/s

and the same formula Vf = m1v1/(m1+m2) sin 125 for the y value which is supposed to come out to be 2.36 m/s.

Thanks !
 
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Go back to basics with conservation of momentum:
[tex]m_1\vec{v_1} + m_2\vec{v_2} = (m_1 + m_2)\vec{v_f}[/tex]

Establish x and y axes, and write expressions for momentum conservation for each direction separately.

Hint: If you define your x-axis to be along the line bisecting that 125 degree angle, your momentum calculations will be greatly simplified.
 

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