Solving Inequalities: How Do I Determine the Correct Answer?

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Discussion Overview

The discussion revolves around solving the inequality (X-4)/X>0, exploring different methods and reasoning for determining the correct solution. Participants examine the nuances of solving inequalities compared to equations, focusing on critical points and sign analysis.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants suggest identifying critical points where the numerator or denominator equals zero to categorize intervals for the inequality.
  • One participant emphasizes that multiplying both sides of an inequality by a negative number reverses the inequality sign, contrasting this with equations.
  • Another participant outlines the sign analysis for the terms in the inequality, noting the conditions under which the expression is positive or negative.
  • There is a proposal to multiply both sides of the inequality by x², with the caveat that x cannot be zero, to maintain the direction of the inequality.
  • A participant expresses confusion about obtaining multiple conditions (x>0 and x>4) and questions their approach.
  • A later reply reiterates the importance of determining the signs of the terms involved and suggests constructing a table to visualize the conditions under which the inequality holds true.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method for solving the inequality, with multiple competing views and approaches presented throughout the discussion.

Contextual Notes

Some assumptions about the behavior of the inequality based on the critical points and sign analysis remain unresolved, and participants do not fully agree on the implications of multiplying by x² or the interpretation of the results.

member 529879
How would I solve the inequality (X-4)/X>0. I thought that inequalities were solved in the same way equations were, but when I solve that way I get X>4 which isn't the entire answer.
 
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For this one, it is best to look at critical points where either the top or bottom equal zero. From that, you should be able to quickly categorize the intervals where the expression is true.
 
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Scheuerf said:
How would I solve the inequality (X-4)/X>0. I thought that inequalities were solved in the same way equations were
No, they're not. For example, if you multiply both sides of an equation by, say, -1, you get a new equation that is equivalent to the one you started with.

If you multiply an inequality by -1, the inequality symbol changes direction.
Scheuerf said:
, but when I solve that way I get X>4 which isn't the entire answer.
 
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Well, what you do is:
x-4: Negative when x<4, positive when x>4
x: Negative when x<0, positive when x>0
Expression: Positive when x<0 (neg. and neg. makes pos.), negative when 0<x<4 and positive when x>4
 
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Svein said:
Well, what you do is:
x-4: Negative when x<4, positive when x>4
x: Negative when x<0, positive when x>0
Expression: Positive when x<0 (neg. and neg. makes pos.), negative when 0<x<4 and positive when x>4
Or, more simply, just multiply both sides of the inequality by x2, first making a note that x cannot be zero. For x ≠ 0, x2 > 0, so the direction of the inequality doesn't change.
 
When I solve that way I get x>0 and x>4. Am I doing something wrong?
 
The correct answer was given in post 4.
##\frac{x-4}{x} >0 ##
Taking Mark44's recommendation, this could also be seen as:
##x^2\frac{x-4}{x} >0*x^2 ##
##x(x-4) >0##
Remember that (-)(-)=(+) and (+)(+)=(+), and (-)(+)=(-) just the same as (-)/(-)=(+) and (+)/(+)=(+), and (-)/(+)=(-).
So whether or not you multiply by ##x^2##, you still need to find the signs of your terms (x-4) and (x) and the appropriate regions.
Build a simple table, the inequality will only hold true if both terms are negative or both are positive.
 
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