Solving Integral: \int_0^{2\pi}\frac{x^n}{\sqrt{1-m\cos x}}dx

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Discussion Overview

The discussion revolves around the calculation of the integral \(\int_0^{2\pi}\frac{x^n}{\sqrt{1-m\cos x}}dx\) for \(0

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant has attempted to use the binomial series expansion of \((1-m \cos(x))^{-1/2}\), leading to integrals of the form \(\int_0^{2\pi} x^n (\cos x)^k dx\).
  • This participant has also replaced \((\cos(x))^k\) with a polynomial of \(\cos(r \cdot x)\) for \(r=1,2,...,k\), resulting in a complex formula that is difficult to utilize further.
  • Another participant suggests using integration by parts \(n\) times to handle the integral \(\int x^n \cos^k(x) dx\).
  • A different approach is proposed involving the expression of \(\cos(x)\) in terms of exponential functions, which may be applicable even for non-integral powers.
  • A participant expresses skepticism about the integration by parts method, noting potential complications when differentiating the cosine term.
  • One participant indicates that their approach aligns with the first participant's method, at least for integer values of \(k\).

Areas of Agreement / Disagreement

Participants have not reached a consensus on the best method to solve the integral, and multiple competing approaches are presented. There is uncertainty regarding the effectiveness of integration by parts in this context.

Contextual Notes

Participants have not fully resolved the implications of their proposed methods, and there may be limitations related to the assumptions made about the powers of cosine and the applicability of integration techniques.

csopi
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Hi,

I need some help to calculate this integral:
[tex]\int _0^{2\pi}\frac{x^n}{\sqrt{1-m\cos x}}dx[/tex], where 0<m<1.

What I've already tried:
took the binomial series of (1-m cos(x))^(-1/2), this results in integrals like

[tex]\int_0^{2\pi} x^n(\cos x)^k dx[/tex]

After this I've replaced cos(x)^k as a polynomial of cos(r*x) (r=1,2,...,k). With this I've managed to get a formula (involving two summas), but it is so ugly that I cannot use them in any furhter calculations.(sorry, I don't know how to make formulas in PF, so I've inserted the LaTex code of it)

Thank You!
 
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You integrate
[tex]\int x^ncos^k(x) dx[/tex]
using integration by parts- n times.

(I have replaced your "$" with [ tex ] to start and [ /tex ] to end the LaTeX- without the spaces.)
 
Also if you are curious you can use the fact that:

[itex]cos(x) = \frac{e^{ix} + e^{-ix}}{2}[/itex] and you can take that to whatever power you want. This even works for non-integral powers where the result is valid.
 
HallsofIvy:
Thank you for your help with the formula. However, I don't see how integration by parts works in this case, because while differentiating the cosine term, I will have some ugly terms.

chiro:
I think that this is exactly the same as what I've done (at least for integer k-s)
 

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