Solving Laplacian in Ex(r,z) Equation

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To solve the Laplacian in the given equation E(r,z), it is essential to clarify the coordinate system being used, as the expression mixes polar and Cartesian coordinates. The correct approach involves either transforming r into Cartesian coordinates or treating z in polar coordinates while applying the appropriate Laplacian. The Laplacian in cylindrical coordinates is defined as the sum of second derivatives with respect to r, θ, and z. This method ensures accurate calculations for the vector Eo. Properly addressing the coordinate system is crucial for successfully solving the Laplacian.
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I need to know the steps involved in solving this laplacian.

Ex(r,z) = Eo*e^[-(r/ro)^2]*e^[-ibz]

the laplacian \/^2*Eo = ?
Eo is a vector
\/ is laplacian symbol

any help would be appreciated.

Thanks in advance.
 
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you probably meant \/^2*Ex, not \/^2*Eo.

Well, the problem is that there are polar and cartesian coordinates mixed up in the expression of Ex. So either transform r in cartesian and use the cartesian laplacian or transform z in polar and use the polar laplacian.
 
No, that's in "cylindrical coordinates" which is perfectly fine- just use polar coordinates with z appended.

The Laplacian of Y in cylindrical coordinates is
\frac{\partial^2 Y}{\partial r^2}+ \frac{1}{r}\frac{\partial Y}{\partial r}+ \frac{1}{r^2}\frac{\partial^2 Y}{\partial \theta^2}+ \frac{\partial^2 Y}{\partial z^2}
 
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