What Are Common Mistakes When Calculating the Laplacian of |r|?

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Homework Help Overview

The discussion revolves around calculating the Laplacian of the function |r|, defined as |r|=√(x^2+y^2+z^2), where r is a vector in three-dimensional space. Participants are exploring the derivatives of this function and the implications for the Laplacian.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the partial derivative of |r| with respect to x, with one participant asserting the result as x/|r|. There is inquiry into the correctness of the Laplacian calculation, with some suggesting that the original poster's result may be incorrect. Questions are raised about the definition of the Laplacian and the steps taken to arrive at the derivative results.

Discussion Status

The discussion is active, with participants providing feedback on each other's calculations and questioning the assumptions made. There is a focus on clarifying the steps involved in the differentiation process, and some participants express a desire for more detailed work from the original poster.

Contextual Notes

There is an emphasis on understanding the definitions and calculations involved in the problem, with participants noting the need for clarity in the steps taken to derive the results. The original poster's calculations are under scrutiny, and assumptions about the Laplacian are being examined.

erb12c
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Homework Statement


Given: |r|=√(x^2+y^2+z^2) r=xi+yj+zk

(i)Find the partial derivative with respect to x of |r|.
(ii) Find the Laplacian of |r|.

Homework Equations

The Attempt at a Solution


For (i) I got x/|r|
but then for (ii) I got 2/r which I don't think is correct
 
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If ##| \vec r(x, y, z) | = \sqrt{x^2 + y^2 + z^2}##, then:

$$| \vec r(x, y, z) |_x = \frac{\partial}{\partial x} (x^2 + y^2 + z^2)^{\frac{1}{2}} = \frac{1}{2} (x^2 + y^2 + z^2)^{- \frac{1}{2}} \cdot \frac{\partial}{\partial x} (x^2 + y^2 + z^2)$$

What is the definition of the Laplacian?
 
Part i) is the warm up for part ii).
What did you do to get x/|r|?

If ##\frac{\partial}{\partial x } |r| = \frac{x}{|r|} ##, then what is ##\frac{\partial}{\partial x } \frac{x}{|r|} ##?

I think 2/|r| is right.
 
RUber said:
What did you do to get x/|r|?

If you clean up the computation in the second post:

$$\frac{1}{2} (x^2 + y^2 + z^2)^{- \frac{1}{2}} \cdot \frac{\partial}{\partial x} (x^2 + y^2 + z^2) = \frac{x}{\sqrt{x^2 + y^2 + z^2}} = \frac{x}{| \vec r |}$$

If ##\frac{\partial}{\partial x } |r| = \frac{x}{|r|} ##, then what is ##\frac{\partial}{\partial x } \frac{x}{|r|} ##?

I think 2/|r| is right.

It is, but it would be nice if the OP showed some of the work.
 

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