Solving Lens Problem: Eyeglasses w/ 2 Converging Lenses

  • Thread starter Thread starter Alt+F4
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around a problem involving two converging lenses, where participants are tasked with determining the image distance and height formed by the first lens, as well as the subsequent effects of the second lens on the light from the first image. The subject area includes optics and lens equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using the thin lens equation to find the image distance and height for the first lens. Some suggest drawing a ray diagram to visualize the problem, while others express uncertainty and seek additional help. There is mention of treating the image from the first lens as an object for the second lens.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to locate the image formed by the first lens. Some guidance has been offered regarding the application of the lens equation and the use of ray diagrams, but there is no explicit consensus on the method or solution yet.

Contextual Notes

Participants are working under the constraints of a homework problem, which may limit the information they can use or the methods they can apply. There is also a note about potential confusion regarding the terms in the lens equation.

Alt+F4
Messages
305
Reaction score
0
Lenses Problem

In the figure are shown two converging lenses with x2 = 1 m. The lens on the left (Lens 1) has a focal length of 0.25 m while the one on the right (Lens 2) has a focal length of 0.2 m. An object 3.9 cm high is located x1 = 0.397 m to the left of Lens 1.


http://img153.imageshack.us/img153/123/showmeal3.gif


--------------------------------------------------------------------------------
(a) Consider the image of the object formed by Lens 1. Give its distance as measured from Lens 1 and the image height.
Distance = m


SO i was trying to use the thins line equation which is 1/ o + 1/f = 1/I but i don't know what numbers to plug in
 
Last edited by a moderator:
Physics news on Phys.org
Drawing the ray diagram for this system of lenses would be very useful. The first lens will form an image. You can use the lens equation to help you locate it. Then think about what the second lense does to the light coming from (or going toward) the image of the first lens.
 
Last edited:
i have no idea, can i get more help
 
Alt+F4 said:
i have no idea, can i get more help
Do the problem as if the lens on the right were not there to locate the image formed by the first lens. It will be between the two lenses. When you know the position of the image, you can also find the height of the image. Use your thin lens formulas.

As far as the second lens knows, the light coming to it from the image of the first lens is light from some object. So treat the image from the first lens as an object for the second lens and do a new problem to find the image formed by the second lens.

Check the lens equation you originally posted. You have some terms mixed up.
 
Last edited:
Here is a diagram that might help you through this. For your part a) you only need the first lens. I assume later parts talk about the second lens. Note that the size of the original image is much larger than scale, which is why the lines are so far off axis. The blue rays are actual paths light could take. The red line through the second lens is added to help locate the final image.

All you need to do is apply the lens equation once to find the image between the lenses, and then a second time to find the final image. The image sizes are determined by the ratio of image distance to object distance.
 

Attachments

  • TwoLens.jpg
    TwoLens.jpg
    13.6 KB · Views: 543
Last edited:

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K