Solving linear equations with exactly one solution

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Homework Help Overview

The discussion revolves around determining the values of k for which a system of linear equations has exactly one solution. The equations in question are x + 2y = 1 and (k^2)x - 2ky = 2, which introduces a parameter k into the system.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of a 2x2 matrix to analyze the system and explore conditions under which the determinant is non-zero to ensure a unique solution. There are questions about the implications of having multiple values for k and whether this aligns with the requirement for exactly one solution.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and questioning the interpretation of the problem. Some guidance has been offered regarding the relationship between k and the solution set, but no consensus has been reached on the values of k that satisfy the condition of having exactly one solution.

Contextual Notes

There is a mention of a duplicate post, which may indicate that the problem has been discussed previously. Participants are also grappling with the implications of the problem statement regarding the uniqueness of the solution in relation to the parameter k.

baki
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1.Determine the value(s) of k for which the system of linear equations
x + 2y = 1
(k2)x - 2ky = 2
has exactly one solution 3.How do i solve this, i tried the 2x2 matrix
whereby, i had
|1 2|
|k2 -2k|
and tried to make [2 and k^2 = zero] and [-2k = one]
But I can't seem to solve it completely
is there another way we can do this?
 
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This is a duplicate post of https://www.physicsforums.com/showthread.php?t=651710
 
baki said:
[ b]1.Determine the value(s) of k for which the system of linear equations
x + 2y = 1
(k2)x - 2ky = 2
has exactly one solution [/b]

[ b]3.How do i solve this, i tried the 2x2 matrix
whereby, i had
|1 2|
|k2 -2k|
and tried to make [2 and k^2 = zero] and [-2k = one]
But I can't seem to solve it completely
is there another way we can do this?
[/b]
Try solving the system, as it is, for x & y.

See how k is involved in that solution.
 
I've tried that and there are 2 values of k, but don't you think when it says it has exactly one solution than it means k should have one value.
 
baki said:
I've tried that and there are 2 values of k, but don't you think when it says it has exactly one solution than it means k should have one value.
No.

It means, "What value or values may k have so that the system has one (x, y) solution?"
 

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