Solving Logarithmic Equation with Real Numbers: Log Problem Homework

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SUMMARY

The logarithmic equation 9^x - 5*3^x + 6 = 0 can be solved by substituting y = 3^x, transforming the equation into a quadratic form: y^2 - 5y + 6 = 0. This quadratic can be factored easily, leading to the solutions for y. Once y is determined, the next step is to solve for x by reverting the substitution 3^x = y.

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Homework Statement



9^x-5*3^X+6=0

Homework Equations



I have no idea how to solve this i suspect there is a theory that I am not familiar with involved.
want real numbers.

The Attempt at a Solution



i thought about moving the 6 to the otherside and doing log on both but you can't have ln(-6)
im clueless. need help thanks.
 
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9= 32 so 9x= (32)x= (3x)2.

Let y= 3x and your equation becomes y2- 5y+ 6= 0, and easily factored quadratic. Once you know y, solve 3x= y.
 

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