Solving Magnetic Field Problem: Reitz-Milford-Cristy 9.15 (4th Ed.)

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Homework Help Overview

This discussion revolves around a problem from Reitz-Milford-Cristy concerning the magnetic field generated by a long wire carrying current above a plane, specifically addressing two cases with different magnetic permeability values. Participants are exploring the implications of boundary conditions on the magnetic scalar potential and the behavior of the magnetic field in relation to the wire and an image current.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the separation of field sources and the application of Laplace's equation to find the magnetic scalar potential. Questions arise regarding the implications of the tangential derivative of the potential on the boundary plane and how it relates to the uniqueness theorem.

Discussion Status

The discussion is ongoing, with participants providing insights into the relationship between the tangential components of the magnetic field and the scalar potential. Some guidance has been offered regarding the implications of boundary conditions, but no consensus has been reached on the overall approach to the problem.

Contextual Notes

Participants are navigating the complexities of boundary conditions and the uniqueness of solutions in the context of magnetic fields, with specific attention to the behavior of the scalar potential at the boundary plane.

facenian
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Homework Statement


This is a problem from Reitz-Milford-Cristy-Problem 9.15(fourth Ed.) .There is a long wire carrying a current "I" above a plane,inside the plane we have to cases a)μ=∞; and b)μ=0. We must find the field above the plane.

Homework Equations


H=∇∅
Δ∅=0


The Attempt at a Solution


To solve the problem we split the field sources: 1)wire + 2)Magnetic plane. Part 1) is already known and to find 2) we put H=-grad∅ and solve laplace equation Δ∅=0. To find ∅ we consider an image current in case a) it is a parallel current and in case b) it is an antiparallel one.
I understand case b), in this case we have B=0 inside the plane so the normal component of H must vanish so the normal derivate of ∅ must cancell that of "I" and the problem is uniquely solved.
However in case a) we have H=0 and the tangencial component of H must vanish, we can do this with a parallel image however in this case what we know is the tangencial derivate of ∅ and the unicity theorem for laplace equation does not apply.
Can someone shed some light on this?
 
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facenian said:
However in case a) we have H=0 and the tangencial component of H must vanish, we can do this with a parallel image however in this case what we know is the tangencial derivate of ∅ and the unicity theorem for laplace equation does not apply.
Can someone shed some light on this?

If the tangential derivative of ∅ vanishes on the boundary plane, what does that tell you about how ∅ varies on the boundary plane?
 
TSny said:
If the tangential derivative of ∅ vanishes on the boundary plane, what does that tell you about how ∅ varies on the boundary plane?
The problem is that the tangencial derivative of ∅ does not vanish but it is equal an opposite to the tangencial component of source 1) (the wire) so the field generated by the to sources combined add up to a null tangencial field
 
OK. I see. ∅ is the magnetic scalar potential of the image current alone.

From the known tangential component of H on the boundary plane due to the true current, you know the tangential component of H due to the image current. So, as you said, you know the value of the component of the gradient of ∅ in the direction of the tangential component of H, ∇t∅(x,y), at each point (x,y) on the boundary plane.

Taking ∅ = 0 at infinity, can you use ∇t∅(x,y) to find (in principle) the value of ∅ at any point of the plane? Does uniqueness follow?
 
TSny said:
Taking ∅ = 0 at infinity, can you use ∇t∅(x,y) to find (in principle) the value of ∅ at any point of the plane? Does uniqueness follow?

Now I see, determining the tangencial component in this case is equivalent to determine the value of ∅ on the boundary surface so uniqueness can be applied. Thank you TSny
 

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