Solving Man's Velocity and Angle Relative to Water

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SUMMARY

The discussion centers on calculating a man's velocity and angle relative to water while he walks on a moving ship. The ship's speed is {v}_{s} = 3 m/s, and the man walks at {v}_{m} = 4 m/s at an angle \theta = 22 degrees to the ship's direction. The correct approach involves vector addition of the ship's velocity and the man's velocity components, leading to a resultant speed of approximately 4.5 m/s relative to the water. Additionally, the angle of his path relative to the water must be recalculated considering the ship's motion.

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The Problem:

Part 1) A ship cruises forward at {v}_{s} = 3 m/s relative to the water. On deck, a man walks diagonally toward the bow such that his path forms an angle \theta = 22 degrees with a line perpendicular to the boat's direction of motion. He walks at {v}_{m} = 4 m/s relative to the boat.

At what speed does he walk relative to the water? Answer in units of m/s. Your answer must be within +/- 5%.

Part 2) At what angle to his intended path does the man walk with respect to the water? Answer in units of degrees. Your answer must be within +/- 5%.


Attempt at a solution:

Part 1) What I did was find the velocity in the direction of the boat he was traveling, and I found that to be ~1.5 m/s. And after that, I simply added that to the 3 m/s that the boat was traveling into find the vector he was traveling at relative to the water to get a vector of 4.5 m/s. However, I'm pretty sure I'm doing this wrong.

Part 2) Wouldn't it just be 0 degrees if I use the 4.5 m/s relative to the water? Again, I'm probably thinking about the entire thing the wrong way.

Any help would be appreciated greatly, thanks guys!
 
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Redstar2 said:
Part 1) What I did was find the velocity in the direction of the boat he was traveling, and I found that to be ~1.5 m/s. And after that, I simply added that to the 3 m/s that the boat was traveling into find the vector he was traveling at relative to the water to get a vector of 4.5 m/s. However, I'm pretty sure I'm doing this wrong.
It's wrong because you ignored the component of his velocity (with respect to the ship) perpendicular to the ship's direction.

Part 2) Wouldn't it just be 0 degrees if I use the 4.5 m/s relative to the water? Again, I'm probably thinking about the entire thing the wrong way.
With respect to the ship, his path makes an angle of 22 degrees away from the ship's direction of motion. But with respect to the water, what is his direction of motion?

To get the relative velocity of person with respect to the water, you must add the two vectors: A (the boat's velocity with respect to the water) + B (the person's velocity with respect to the boat). Hint: Use components.
 

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