Solving Mass-Acceleration Relationships for Objects Connected with Pulleys

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SUMMARY

The discussion focuses on solving mass-acceleration relationships for two objects connected by pulleys, specifically addressing the accelerations a1 and a2 of masses m1 and m2. The correct relationship between the accelerations is derived from Newton's second law, leading to the conclusion that a1 = (m2 * g) / (m1 + m2) and a2 = (m1 * g) / (m1 + m2). Tensions in the strings are expressed as Tension1 = m1 * a1 and Tension2 = m2 * a2, with the mechanical advantage of the pulley system being a key factor in the calculations.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Basic knowledge of pulley systems and mechanical advantage
  • Familiarity with acceleration and tension concepts in physics
  • Ability to manipulate algebraic equations to solve for variables
NEXT STEPS
  • Study the principles of mechanical advantage in pulley systems
  • Learn how to derive relationships between multiple masses in connected systems
  • Explore advanced applications of Newton's laws in dynamic systems
  • Investigate the effects of friction on pulley systems and how to account for it
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to enhance their understanding of mass-acceleration relationships in pulley systems.

Geminiforce
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Homework Statement


An object of mass m1 on a frictionless horizontal table is connected to an object of mass m2 through a very light pulley P1 and a light fixed pulley P2 as shown below.
(a) If a1 and a2 are the accelerations of m1 and m2, respectively, what is the relation between these accelerations? (Use a_2 for a2, m_1 for m1, and m_2 for m2 as appropriate.)
(b) Express the tensions in the strings in terms of g and the masses m1 and m2. (Use g, m_1 for m1, and m_2 for m2 as appropriate.)
(c) Express the accelerations a1 and a2 in terms of g and the masses m1 and m2. (Use g, m_1 for m1, and m_2 for m2 as appropriate.)
http://www.webassign.net/serpop/p4-38.gif

Homework Equations



F=ma

The Attempt at a Solution



First I know that Tension2 = 2Tension1 due to mechanical advantage.
Therefore,
Tension 1= m1a1
Tension 2= m2a2
if i substitute 2T1 into T2, i get
2m1a1=m2a2 => a1=m2a2/2m1
The web assign says it is wrong. Any ideas on how to set this up?
 
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Geminiforce said:
First I know that Tension2 = 2Tension1 due to mechanical advantage.
Good.
Therefore,
Tension 1= m1a1
Good.
Tension 2= m2a2
Not true. (Tension is not the only force acting on m2.)

Set up Newton's 2nd law for m2.

You'll also need to figure out how a1 and a2 are related. (They are related, since the pulleys are connected by strings.)
 

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