Solving Material Balance Problems in Evaporators

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SUMMARY

The discussion focuses on solving material balance problems in evaporators, specifically regarding an aqueous solution containing 15% NaOH and 0.5% NaCl being concentrated at a rate of 100 kg/min. Participants clarify that this rate refers to the mass of the solution entering the evaporator. The analysis of the final mixture shows a concentration of 40% NaOH and 0.8574% NaCl, prompting calculations for the original solution's concentration, the concentrate's composition, and the mass of water evaporated. The problem emphasizes the importance of knowing the composition of the incoming solution for accurate calculations.

PREREQUISITES
  • Understanding of material balance equations in chemical engineering.
  • Knowledge of concentration calculations for solutions.
  • Familiarity with evaporator operation principles.
  • Basic skills in algebra for solving equations.
NEXT STEPS
  • Study material balance equations in evaporators.
  • Learn about concentration and dilution calculations in chemical processes.
  • Explore the principles of mixing solutions in chemical engineering.
  • Investigate the impact of solution composition on evaporation rates.
USEFUL FOR

Chemical engineers, process engineers, and students studying material balance in evaporators will benefit from this discussion.

blackbeauty
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I have an issue with this question:

An aqueous solution containing 15% NaOH and 0.5% NaCl is concentrated at a rate of 100 kg/min in an evaporator. The concentrated solution is then mixed with 2000 kg of aqueous NaOH solution in a mixer. At the end of one hour a sample is collected from the mixer and analysed. The analysis shows 40% NaOH and 0.8574% NaCl. Calculate:

1. The concentration of the original solution in the receiver
2. The composition of the concentrate from the evaporator
3. The mass of water (in kg) evaporated in one hour.When it says that the solution in concentrated at a rate of 100 kg/min, does it mean that the amount entering the evaporator is 100kg in one minute? Or is it the amount leaving the evaporator?

Can this problem be solved without knowing the composition of the 2000 kg aqueous NaOH entering the mixer?
 
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Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 

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