Solving Matrix Eigenvalue Equation for ψ_{200} and ψ_{210} States

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SUMMARY

The discussion focuses on solving the matrix eigenvalue equation for the ψ_{200} and ψ_{210} states in the context of perturbation theory applied to the hydrogen atom. The matrix equation Ux=λx is established, where U represents the matrix elements of H_{1}= eEz between the specified states. The eigenvalues obtained are λ_{1}=3ea_{o}|E| and λ_{2}=-3ea_{o}|E|, leading to the eigenvectors x_{1} =(1/√2 1/√2)^{T} and x_{2}= (1/√2 -1/√2)^{T}. The final states are expressed as linear combinations: ψ_{1} = (ψ_{200} + ψ_{210})/√2 and ψ_{2} = (ψ_{200} - ψ_{210})/√2, illustrating the concept of degeneracy in quantum mechanics.

PREREQUISITES
  • Understanding of matrix eigenvalue equations
  • Familiarity with perturbation theory in quantum mechanics
  • Knowledge of quantum states and their representations
  • Basic concepts of linear combinations in vector spaces
NEXT STEPS
  • Study matrix diagonalization techniques in quantum mechanics
  • Explore perturbation theory applications in hydrogen atom states
  • Learn about degeneracy and its implications in quantum systems
  • Investigate the mathematical formulation of linear combinations of quantum states
USEFUL FOR

Quantum physicists, students of quantum mechanics, and researchers focusing on hydrogen atom behavior under perturbation theory will benefit from this discussion.

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In order to apply perturbation theory to the ψ[itex]_{200}[/itex] and ψ[itex]_{210}[/itex] states, we have to solve the matrix eigenvalue equation.

Ux=λx where U is the matrix of the matrix elements of H[itex]_{1}[/itex]= eEz between these states.

Please see the matrix in attachment 1.

where <2,0,0|z|2,1,0>=<2,1,0|z|2,0,0>=3a[itex]_{o}[/itex]

Solving this matrix we get, λ[itex]_{1}[/itex]=3ea[itex]_{o}[/itex]|E| and λ[itex]_{2}[/itex]= -3ea[itex]_{o}[/itex]|E|

Then we find eigenvectors to get x[itex]_{1}[/itex] =(1/√2 1/√2)[itex]^{T}[/itex] and x[itex]_{2}[/itex]= (1/√2 -1/√2)[itex]^{T}[/itex]

**** They finally said that ψ[itex]_{1}[/itex] = (ψ[itex]_{200}[/itex] + ψ[itex]_{210}[/itex])/√2

and ψ[itex]_{2}[/itex] = (ψ[itex]_{200}[/itex] - ψ[itex]_{210}[/itex])/√2

How did they get this? How did they combine ψ[itex]_{1}[/itex] and ψ[itex]_{2}[/itex] as follows? It is just the linear combination that I don't get. Thank you.
 

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Please note that this is for Hydrogen atom, n=2 where we have degeneracy!
 

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