Undergrad Solving Navier Stokes & energy equations with different coordinates

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The discussion focuses on fluid analysis of water in a subsea pipe using the Navier-Stokes equations. The user derived a velocity equation in cylindrical coordinates but initially solved the energy equation in Cartesian coordinates. They question whether differentiating their velocity result and substituting it back into the energy equation is valid. Another participant suggests using the energy equation in cylindrical coordinates for simplicity, noting that the model is only valid if temperature depends solely on the radius. The consensus is that working within a single coordinate system is preferable for clarity and accuracy.
shevir1
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Hi all I am conducting a fluid analysis on water flowing through a subsea pipe.

Having used navier stokes equation, i derived the equation for velocity in the r-direction (using cylindrical coordinates.

But when initially solving the energy equation to determine temperature distribution I have used the cartesian coordinates, x & y

From the picture I have attached am I correct in proceeding to solve the energy equation, if I were to just differentiate my velocity equation result and substitute back into the energy equation?
From my knowledge the Y direction in cartesian corresponds with the R direction in the cyclindrical hence my reasoning for proceeding this way.
 

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shevir1 said:
From my knowledge the Y direction in cartesian corresponds with the R direction in the cyclindrical hence my reasoning for proceeding this way.
These are the actual relationships between cylindrical and cartesian coordinates.
x = r \cos \theta
y = r \sin \theta
r^2 = x^2 + y^2
Why don't you just use the energy equation in cylindrical coordinates? That's the easiest way to proceed.
\frac{1}{r} \frac{d}{dr} \left( r \frac{dT}{dr} \right) = - \frac{\mu}{k} \left( \frac{dv_z}{dr} \right)^2
However, this model is only valid if the temperature is a function of radius only. If it also depends on z, your energy equation becomes a PDE.
 
yes this is what i assumed.
of course it is better to work in just one coordinate system.

thanks
 

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