Solving Net Force with (g), sin(θ) & μcos(θ)

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chezholmes
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Homework Statement
An Olympic skier moving at 33 m/s down a 22◦ slope encounters a region of wet snow of coefficient of kinetic friction μ = 0.78.
The acceleration of gravity is 9.8 m/s2 .
How far down the slope does she travel before coming to a halt?
Answer in units of m.
Relevant Equations
Newton's second law equation
kinematic equations
Ff = μ*Fn
Tried net force = (g)sin(θ)- μ(g)cos(θ)
 
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chezholmes said:
Homework Statement: An Olympic skier moving at 33 m/s down a 22◦ slope encounters a region of wet snow of coefficient of kinetic friction μ = 0.78.
The acceleration of gravity is 9.8 m/s2 .
How far down the slope does she travel before coming to a halt?
Answer in units of m.
Homework Equations: Newton's second law equation
kinematic equations
Ff = μ*Fn

Tried net force = (g)sin(θ)- μ(g)cos(θ)
Net force as you have it is actually 'net acceleration'. Well that's fine - select correct equation of motion to solve for displacement down the slope.