Solving OCR M2 Questions: Bullets and Equations

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Homework Help Overview

The discussion revolves around a physics problem related to projectile motion, specifically focusing on a bullet fired from a height and its trajectory. The problem involves analyzing the equations governing the bullet's motion and determining the maximum horizontal distance it can achieve based on varying launch angles.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the trajectory equation and its implications, questioning whether to treat the problem as if the launch point is at ground level or to adjust for the height of the launch. There is also a request for clarification on the significance of the trajectory equation and its application.

Discussion Status

The conversation is ongoing, with some participants suggesting that adjustments for elevation should be made while others are exploring the implications of the trajectory equations. There is a recognition of the complexity introduced by the launch height, but no consensus has been reached on the approach to take.

Contextual Notes

Participants note the challenge of understanding the problem without direct guidance, as one member is studying independently. The original poster's equations assume a certain setup that may not align with the actual conditions described.

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Homework Statement



some ocr m2 questions

Homework Equations




-
P]
]
]
]
b]
]
]
]
]
O]-----------------------------------------------Q
x

A BULLETis fired at position P with speed √ag (g=9.8) at an angle z above the horizontal, where a is a constant. P is at vertical height b ablve the horizontal plane. The bullet strikes the plane at the point Q and O is the point at the level of the plane vertically below P, as shown. Letting OQ=x

x^2 tan z - 2axtan z +( x^2 -2ab) =0
show maximum value of x as z varies is √ a(a+2b) and that is archieved when Tan Z =√ a/a+2b

The Attempt at a Solution

 
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What direction do you think you need to take this problem?
 
erm the equation look like the trajectory
the problem is these quations assumsed that the particle is on ground level, so shud i just do it that way then?? or make adjustment to the equations given like greatest height reached , time returning to its originalheight and range on horizontal ground??
y= ut +0.5gt^2
 
Don't assume it's on ground level.

The tricky thing about trajectory is that the angle which gives the farthest horizontal distance at any given velocity is below 45 degrees when you raise the launch platform.

It's not much more difficult to solve as if it were on the ground, though. Just account for the elevation, b.
 
can u explain to the trajectory equation and its significance and stuff cos i am doing M2 myself without a teacher so i m finding it difficult to grasp some of the important concept and implications from the equations. like how to use it and why??
 

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