Solving ODE: 2y(1+x^2√y)dx + x(2+x^2√y)dy = 0 | Step-by-Step Guide

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SUMMARY

The discussion focuses on solving the ordinary differential equation (ODE) represented by the equation 2y(1+x^2√y)dx + x(2+x^2√y)dy = 0. Participants suggest substituting x^2√y with u to simplify the differentiation process. The correct differentiation leads to a more manageable form, confirming that the ODE is separable. Additionally, the method of grouping terms into perfect differentials is proposed, allowing for the application of linear ODE techniques.

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Homework Statement


[tex]2y(1+x^2\sqrt{y})dx + x(2+x^2\sqrt{y})dy = 0[/tex]

The Attempt at a Solution


well, I substituted x^2√y=u but then when I tried to differentiate it I understood it would be so hard. Please check and see if I've differentiated it correctly:

√y = u/x^2 -> y = u^2.x^-4 -> dy/dx = 2u.u'x^(-4) - 4x^(-5).u^2
Is that correct? if yes, then I think I've just made the problem harder. how can I solve that ODE?
 
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It is correct. Substitute for y and y' in the original equation, simplify and arrange: it is a separable ODE.

ehild
 
You could try grouping the terms into perfect differentials. For example, 2 y dx + 2 x dy = 2 d(xy). The other two terms can be written similarly as d(something) . Then write u = xy and v = something and it is a simple linear ODE.
 

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