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solve dy/dx = (x+y)^2 , y(0)=1
i let w = (x+y) and got the above equation rearranged to dw/dx - 1=w^2
after solving for C i got y=tan(x-pi/4) - x
just wanted to check my answer
i let w = (x+y) and got the above equation rearranged to dw/dx - 1=w^2
after solving for C i got y=tan(x-pi/4) - x
just wanted to check my answer