- #1

- 13

- 0

i let w = (x+y) and got the above equation rearranged to dw/dx - 1=w^2

after solving for C i got y=tan(x-pi/4) - x

just wanted to check my answer

- Thread starter mat331760298
- Start date

- #1

- 13

- 0

i let w = (x+y) and got the above equation rearranged to dw/dx - 1=w^2

after solving for C i got y=tan(x-pi/4) - x

just wanted to check my answer

- #2

lanedance

Homework Helper

- 3,304

- 2

w = (x+y) then

dw/dx = 1+dy/dx

dw/dx = 1 + w^2

this part looks ok

- #3

lanedance

Homework Helper

- 3,304

- 2

then

w = x+y=x+(tan(x-pi/4)-x) = tan(x-pi/4)

dw/dx = sec(x-pi/4)^2 = 1+tan(x-pi/4)^2

- #4

lanedance

Homework Helper

- 3,304

- 2

just remains to check IC

w(0) = tan(-pi/4)

does that look correct?

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