Solving Partial differential equation

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The discussion centers on solving a differential equation that initially appears to be a partial differential equation (PDE) but is identified as an ordinary differential equation (ODE) due to the dependence of the function ##\psi## solely on the variable y. The equation is given as $$\frac{\partial^{2}\psi(\sqrt{g} y)}{\partial y^{2}}=(\frac{sin^{2}(\sqrt{g}y)}{g}-\frac{2E}{\omega})\psi\sqrt{g}y$$, with boundary conditions at ##\frac{\pi}{2}## and ##\frac{-\pi}{2}##. A suggested approach involves substituting ##u = \sqrt{g} y## to simplify the equation, leading to a nonlinear ODE. The conversation also touches on the potential for using an integrating factor or exploring series solutions, although challenges remain due to the equation's complexity. Overall, the focus is on finding a method to solve this nonlinear ordinary differential equation effectively.
AHSAN MUJTABA
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Homework Statement
solve the equation for $$\frac{\partial^{2}\psi(\sqrt{g} y)}{\partial y^{2}}=(\frac{sin^{2}(\sqrt{g}y)}{g}-\frac{2E}{\omega})\psi(\sqrt{g}y)$$.
Relevant Equations
The boundary conditions are $$\psi(\frac{\pi}{2})=0$$ and $$\psi(\frac{-\pi}{2})=0$$. I know the values of ##\frac{E}{\omega}##
I have tried to do it in standard way by integrating in PDE's but it turned out that ##\psi## is a function of y, so now I have no clue to start this. I know the range of ##\sqrt {g}y## from ##\frac{-\pi}{2}## to ##\frac{\pi}{2}##
 
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AHSAN MUJTABA said:
Homework Statement:: solve the equation for $$\frac{\partial^{2}\psi(\sqrt{g} y)}{\partial y^{2}}=(\frac{sin^{2}(\sqrt{g}y)}{g}-\frac{2E}{\omega})\psi\sqrt{g}y$$.
Relevant Equations:: The boundary conditions are $$\psi(\frac{\pi}{2}=0$$ and $$\psi(\frac{-\pi}{2})=0$$. I know the values of ##\frac{E}{\omega}##

I have tried to do it in standard way by integrating in PDE's but it turned out that ##\psi## is a function of y, so now I have no clue to start this. I know the range of ##\sqrt {g}y## from ##\frac{-\pi}{2}## to ##\frac{\pi}{2}##
Since ##\phi## is apparently a function of y alone, it seems to me that you're not dealing with a partial differential equation -- just an ordinary differential equation. An integrating factor might work.
 
Mark44 said:
Since ##\phi## is apparently a function of y alone, it seems to me that you're not dealing with a partial differential equation -- just an ordinary differential equation. An integrating factor might work.
If I just double integrate this equation on y, you mean that?
 
I was thinking of some series solutions but I have to solve it properly
 
AHSAN MUJTABA said:
If I just double integrate this equation on y, you mean that?
No, that's not what I mean. I would first do a substitution -- Let ##u = \sqrt g y## -- and then get a DE that looks like this:
##\frac{d^2 \phi(u)}{du^2} - (\frac{\sin^2(u)} u - \frac {2E} \omega)\phi(u) = 0##
It won't look exactly like this, because there are some factors that I've omitted that come from the chain rule.

This is an ordinary differential equation, not a PDE, but it's nonlinear. I don't have any ideas for attacking it at the moment.
 
I have tried to attack it with the same strategy but since ##\phi(u)## at the end creates a high problem for solving this.
 
Can I substitute appropriately to make it a first order ode?
 
AHSAN MUJTABA said:
Can I substitute appropriately to make it a first order ode?
No, because you have ##\phi''## and ##\phi## in the equation.
 
Is there going to be a power series solution?
 

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