Solving Pascals Principle for Hydraulic Jack - F2 = 10.8N

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SUMMARY

The discussion centers on solving Pascal's Principle in the context of a hydraulic jack, where a force of 120 N is applied to the handle. The pressure relationship is established as P1 = P2, leading to the equation P2 = F2 * 0.025² * π. The participant successfully calculates the load supported by the jack, F2, as 10.8 N, confirming the interpretation of the problem is correct.

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Homework Statement


A hydraulic jack has the dimensions as shown in the figure to the left. A force F of 120 N is exerted on the handle of the jack. What load, F2, is being supported by the jack?


Homework Equations


P1=P2
P=F/A


The Attempt at a Solution



I know that P1=P2
And P2 = F2*0.025^2*pi
What I am having trouble with is P1. I never seen a hydraulic jack before so I don't quite understand how that pressure works there. My guess here would be 120*A1=F2*0.025^2*pi
Solving for F2 gives 10.8N. Did i interpret the question correctly?
 
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