Solving Physics Problem: Find Distance up Incline (Grade 11)

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Homework Help Overview

The discussion revolves around a physics problem concerning the distance a block slides up an incline. The scenario involves a block with a mass of 3.3 kg on a 38-degree incline, with a coefficient of friction of 0.21 and an initial speed of 5.75 m/s. Participants are exploring different methods to determine how far the block will slide up the incline.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to solve the problem using two methods, one involving net force and kinematics, and the other using energy principles. Some participants question the setup and the equations used, while others suggest using conservation of mechanical energy to approach the problem.

Discussion Status

The discussion is ongoing, with participants providing insights into different approaches. Some guidance has been offered regarding the use of conservation of energy, but there is no explicit consensus on the correct method or solution yet.

Contextual Notes

Participants are working under the constraints of a grade 11 physics assignment, which may influence the methods and reasoning discussed. There is also a note about the importance of including the full question for clarity.

RebWal
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I don't know how to solve for s. The question is How far up the incline will the block slide, and I was to solve it 2 ways.

I think I got the first way, and this is what I have so far for the 2nd way.

w=e2-e1
-Ff*s=e2-e1
-Moo g Cos pheta*s=1/2v^2-gh
-.21(9.8)Cos38*s=1/2(5.75)^2-9.8[s(Sin38)]

I'm not sure how to solve for s. If anyone could help me out I'd really appreciate it.

Oh by the way, this is grade 11 physics, and the first way I did it was using Fnet=ma and substituting a into v2^2=v1^2+2as and I got s=14m -- Not positive if that is right
 
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RebWal said:
I don't know how to solve for s. The question is How far up the incline will the block slide, and I was to solve it 2 ways.

I think I got the first way, and this is what I have so far for the 2nd way.

w=e2-e1
-Ff*s=e2-e1
-Moo g Cos pheta*s=1/2v^2-gh
-.21(9.8)Cos38*s=1/2(5.75)^2-9.8[s(Sin38)]

I'm not sure how to solve for s. If anyone could help me out I'd really appreciate it.

Oh by the way, this is grade 11 physics, and the first way I did it was using Fnet=ma and substituting a into v2^2=v1^2+2as and I got s=14m -- Not positive if that is right
Although it's great that you included your work, the question would be nice, too.
 
I included the question. It is: How far up the incline will the block slide? The block is 3.3kg, and the angle of incline is 38 degrees. Coefficient of friction is .21 and the speed is 5.75 m/s
 
You can solve the problem using the principle of the conservation of mechanical energy. The Kinethic energy in t=0 has to be equal to the potential energy it its maximum height plus the energy it lost due to friction which is ( (Coef. of fric.)(Normal)(distance travelled) ). You get its max. height using trigonometry you know that sen38 = height/distance travelled. there you go.
 

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