1. The problem statement, all variables and given/known data Hi! I'm having issues with this practice problem. Any advice on what I'm doing wrong would help!!! A 2.5 kg particle is projected with an initial speed of 3.3m/s along a surface for which the coefficient of friction is 0.7. Find the distance it travels given that the particle moves up a 26 degree incline. 2. Relevant equations W=ΔKE W=F*d Ff=μFn W=ΔKE+ΔPE KE=1/2mv2 PE=mgh 3. The attempt at a solution mg=2.5kg*-9.8m/s2=-24.5N -24.5Nsin26=-10.74 N = mgx -24.5Ncos26=-22.02N = mgy ΣFy=0=Fn-mgy Fn= 22.02 N Ff = Fnμ Ff = 22.02N*0.7 Ff=15.14 N W= KEf-KEf+PEf-PEi W=.5mv2-.5mv2+mgh-mgi W=0.5*0.3kg*(3.3m/s)2-0+2.5kg*9.8*h-0 W=F*d Here I assumed KEf was 0 because the final velocity is 0, and I assumed PEi was 0 because the inital height is 0. The forces applied that aren't in equilibrium are mgx, and Ff. W= (-15.14N-10.74N)*d -26.15N*d=0.5*0.3kg*(3.3m/s)2-0+2.5kg*9.8*h So instead of having 2 unknown variables, I made h equal to... h= d*sin26 So.. I inserted that in the previous equation: -26.15N*d=0.5*0.3kg*(3.3m/s)2-0+2.5kg*9.8*d*sin26 Factored out d... d(-26.15+24.5sin26)=-13.6125 d=-13.6125/(-26.15+24.5sin16) d=0.88m And this answer is incorrect. I am unsure where I went wrong... Any thoughts? Thank you!!! For an image of what my free body diagram looks like, I posted it below!!