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## Homework Statement

A ring (hollow cylinder) of mass 2.61kg, inner radius 6.35cm, and outer radius 7.35cm rolls (without slipping) up an inclined plane that makes an angle of θ=36.0°, as shown in the figure below. At the moment the ring is at position

*x*= 2.19m up the plane, its speed is 2.61m/s. The ring continues up the plane for some additional distance and then rolls back down. It does not roll off the top end. How much further up the plane does it go?

## Homework Equations

##T=RF=I\alpha##

##\omega_f^2=\omega_i^2+2\alpha d##

## The Attempt at a Solution

My proposed way to solve the problem is this:

I calculated the gravitational force down the ramp. This force is 15.034 N. It exerts a torque on the hoop of ##15.034N\times 0.0735 m##. Torque is also equal to ##I\alpha##. I can calculate ##I##. Dividing by it will give me angular acceleration. Then I can solve for the angular distance it takes for the hoop to stop rolling up the hill. Does this approach make sense?