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## Homework Statement

An object was launched from the top of a cliff at some angle with an acceleration of 50 ft/sec that overcame gravity. The fuel tank ran out after 2 seconds of flight and gravity took over from that point forward. The object reached a maximum height of 310 ft, was in the air for a total of 9.16 seconds and traveled a horizontal distance of 383 ft.

Find:

Initial Launch Angle

Height of the cliff

Initial vertical velocity

Initial horizontal velocity

## Homework Equations

s(t)=1/2at^2+vt+s

d=1/2at^2

Vf=Vi+at

## The Attempt at a Solution

I think I may have found the launch angle by using the 1/2at^2 equation and plugging in 383=1/2ax(9.16)^2 and 310=1/2ay(9.16)^2. I found the angle to be 39.36, but I am unsure if it is correct, after that I am stuck, help is greatly appreciated.