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Good show.lollikey said:I got it ! the answer is (4f-7mg) / 7m
The discussion focuses on solving a physics problem involving two construction workers of mass m raising themselves on a platform with mass 0.5m using pulleys. The key forces identified include the weight of the workers, the tension in the ropes, and the normal force from the platform. The final equations derived are 2N - 2F - 2mg = 2Ma for the workers and 2f - 0.5mg - 2N = 0.5Ma for the platform, leading to the acceleration formula a = (4f - 7mg) / 7m when the platform mass is increased to 5m.
PREREQUISITESStudents studying physics, particularly those focusing on mechanics, as well as educators looking for examples of force analysis in pulley systems.
Good show.lollikey said:I got it ! the answer is (4f-7mg) / 7m
Draw a line across just below the pulleys. How many ropes cross that line? What is the tension in each?Poetria said:Well, I can't understand why there are 4f and not 2f. I thought it was mechanical advantage but these pulleys are fixed to the ceiling, aren't they? I am obviously missing something.
Right.Poetria said:I see. There are four ropes and each of them has tension f.