Solving Q1 and Q2 of F(x) = 4x^2+6

[tomtomtom1]

Hi all

I was hoping someone could shed light on the following:-

F(x) = 4x^2+6

Q1) Find F(x)+4
Q2) Find F(x+4)

Q1) Am i correct in thinking that 4 is added to the entire function because the +4 is outside of the bracket, so the result will be:-

F(x)+4 = 4x^2+6+4
F(x)+4 = 4x^2+10

Is my thinking correct?

Q2) Am i correct in thinking that 4 is added to the variable x before is it is passed into the function F(x)? So the result would be:-

F(x+4) = 4(x+4)^2+6

So using actual numbers the result would be:-

x F(x) F(x+4)
-3 42 10
-2 22 22
-1 10 42
0 0 70
1 10 106
2 22 150
3 42 202



Is this correct?

Thanks

 

[adjacent]

Yes. You are correct. Why did you make a table for that?for a graph?