(x^2 - 9)(x^2 - 16) ≤ 0
(x - 3)(x + 3)(x - 4)(x + 4) ≤ 0
Setting each factor to 0, we get x = 3, -3, 4, and -4.
Our number line:
<---------(-4)------(-3)-----(3)-----(4)-------->
When x = -4, we get a true statement. The same can be said for x = -3, 3, and 4. This means they are part of the solution.
I will test each interval AGAIN for algebra practice.
For (-infinity, -4), let x = -5. False statement for sure.
For (-4, -3), let x = -3.5. True statement.
For (-3, 3), let x = 0. False statement.
For (3, 4), let x = 3.5. True statement.
For (4, infinity), let x = 6. False statement.
I understand why the solution is [-4, -3] U [3, 4].
So, any value of x in the intervals [-4, -3] and [3, 4] including -4, -3, 3, and 4 satisfy the given inequality. I may post two more quadratic inequality to get additional practice.