Solving Rotational Motion Problem: Get Answer for Revolutions

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Homework Help Overview

The discussion revolves around a rotational motion problem involving a rotor's revolutions before coming to rest. Participants are exploring the application of kinematic equations in this context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to determine the number of revolutions. There are questions about the conversion of angular velocity from RPM to revolutions per second and the correct application of angular acceleration in calculations.

Discussion Status

Some participants have shared their attempts and calculations, while others are questioning the assumptions made regarding angular acceleration and the conversion between radians and revolutions. There is an indication that some guidance has been offered regarding common errors in the calculations.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may impose specific methods or formats for presenting their solutions. There is a focus on ensuring the correct signs for angular quantities in the equations used.

Jason03
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heres the problem I am working on

http://img55.imageshack.us/img55/8568/urgei5.jpg

I got the first part but I can't get the correct answer to how many revolutions the rotor executes before coming to rest...


I tried using the kinematic equations but can't come up with 27,900 revolutions, which is the answer...

any ideas?
 
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Can you show your attempt at the question please?
 
http://img502.imageshack.us/img502/2429/rolg1.jpg
 
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Jason03 said:
http://img502.imageshack.us/img502/2429/rolg1.jpg

So you know [itex]\omega=9300RPM[/itex]

which means that in 1 min. there are 9300 revolutions, OR in 60s there are 9300 revs.
How much in 1s now?

and also, you didn't really need to convert the angular velocity to rad/s and time to seconds since they gave you it in RPM and minutes respectively.
 
Last edited by a moderator:
Hi Jason03,

Jason03 said:
heres the problem I am working on

http://img55.imageshack.us/img55/8568/urgei5.jpg

I got the first part but I can't get the correct answer to how many revolutions the rotor executes before coming to rest...


I tried using the kinematic equations but can't come up with 27,900 revolutions, which is the answer...

any ideas?

I think the kinematic equation should give you 27900 revolutions. Can you post what numbers you used in the kinematic equations that gave you a different [itex](\Delta\theta)[/itex]? A common error when solving for theta is to forget to make the angular acceleration negative when it is slowing down (the angular acceleration and initial angular velocity need to have opposite signs) but without seeing the numbers you used there's no way to tell.
 
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i tried using


theta = 0 + 973.8 -.5(-2.7)(360)^2
 
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i figured out the problem...

the equ. is

[tex]\omega^2 = \omega_{o} + 2\alpha(\theta-\theta_{o})[/tex]

[tex]973.8^2 = 0 -2(2.7)(\theta)[/tex]

[tex]\theta = -175.6 e ^3[/tex]

The problem I was having is converting the last part from radians to revolutions...I realized all I had to do is divide the 175.6e^3 by[tex]2\pi[/tex]...however when I entered that into my calculator like this [tex]175.6e3/2\pi[/tex]...I came up with the wrong answer...I had to enter it as [tex]175.6e3/(2\pi)[/tex]...which gives you 27.9e^3...:)
 

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