Solving Rotations Homework: Double Speed vs Halving Radius

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SUMMARY

The discussion centers on the effects of changing speed and radius on the acceleration of a truck driving around a circular track. Using the formula a = v²/R, calculations show that doubling the speed from 15 m/s to 30 m/s results in an acceleration of 9 m/s², while halving the radius from 100 m to 50 m yields an acceleration of 4.5 m/s². Therefore, it is established that doubling the speed has a greater impact on acceleration than halving the radius.

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  • Understanding of circular motion dynamics
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  • Basic algebra for manipulating equations
  • Knowledge of units of measurement (meters, seconds)
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  • Explore the effects of varying both speed and radius simultaneously
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Homework Statement


A truck was driven around a circular track. Which would have a greater effect on the magnitude of its acceleration: moving to a track with half the radius or doubling the speed.
Show proof/sample calculations.

Homework Equations


I'm not quite sure but I went ahead and tried this equation:
a = v^2/R

The Attempt at a Solution


I tried plugging in numbers:
a = v^2/R
v= 15m/s
R = 100m
a= (15^2)/(100) = 2.25 m/s^2

doubled speed:
a= (30^2)/100 = 9 m/s^2

half radius
a = (15^2)/50 = 4.5 m/s^2

If I'm correct, doubling speed will affect the magnitude of the acceleration more than the halved radius, right?
Thank you so much!
 
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Yes that is correct since whatever factor you multiply the velocity by, becomes squared as well.

a=v2/r

if 'v' is replaced by 'kv', then a' = k2 (v2/r) = k2a
 
rock.freak667 said:
Yes that is correct since whatever factor you multiply the velocity by, becomes squared as well.

a=v2/r

if 'v' is replaced by 'kv', then a' = k2 (v2/r) = k2a


thank you very much for confirming my answer! :smile:
 

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