Solving Schroedinger's equation for Step Potential

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SUMMARY

This discussion focuses on solving Schrödinger's equation for a particle encountering a step potential, specifically where the potential energy V is zero for x<0 and V=Vo for x>0. The time-independent Schrödinger's equation is presented as -h²/2m d²ψ/dx² = Eψ for the first region and -h²/2m d²ψ/dx² = (Vo-E)ψ for the second region. A key point clarified is that while the potential energy and kinetic energy differ across regions, the total energy E remains constant due to the conservation of energy principle.

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uday1236
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Consider the case for a particle with energy E in a region where :
V = 0 , x<0; V=Vo, x>0;
for the first region when we write Schrödinger’s equation(Time independent) it will be
-h^2/2m d2ψ/dx2 = Eψ

and for second region it was
-h^2/2m d2ψ/dx2 = (Vo-E)ψ;


My doubt is that won't the Energy E be different in the second region because the particle experiences an impulse at x=0.

The case is where E<Vo.
 
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The potential energy U and the kinetic energy E - U are of course different in the two regions, but the total energy E is the same everywhere, by conservation of energy.
 
ok thanks...how could i forget E was total energy.
 

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