SUMMARY
The series \(\sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}}\) diverges. By rewriting the series as \(\sum_{n=1}^{\infty}\frac{1}{n e^{\frac{1}{n} \ln n}}\) and applying the limit comparison test, it is established that \(\lim_{n\rightarrow\infty}\frac{1/ne^{\frac{1}{n}\ln n}}{1/n}=1\). Since the harmonic series \(\sum_{n=1}^{\infty}\frac{1}{n}\) diverges, the original series also diverges.
PREREQUISITES
- Understanding of infinite series and convergence tests
- Familiarity with the limit comparison test
- Knowledge of exponential functions and logarithms
- Basic calculus concepts, particularly limits
NEXT STEPS
- Study the properties of the harmonic series and its divergence
- Learn more about the limit comparison test in series convergence
- Explore other convergence tests such as the ratio test and root test
- Investigate the behavior of exponential functions as \(n\) approaches infinity
USEFUL FOR
Students studying calculus, mathematicians analyzing series convergence, and educators teaching convergence tests in mathematical analysis.