Solving series-parallel circuits

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The discussion focuses on solving a series-parallel circuit using the voltage divider rule to find the voltage drop across resistor R4. The user calculated the total resistance as 383Ω, total current as 0.03A, and current through R3 as 0.023A, leading to a voltage of 2.97V across R1 and R2. They determined that the voltage for the rest of the circuit is 9.03V, and calculated the voltage across R4 and R5 to be 1V. However, there is uncertainty about the correctness of these calculations, and a request for detailed step-by-step work on the resistance reduction was made to verify the methods used.
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Summary:: Solving series-parallel circuits using current and voltage divider rule

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For the attached circuit, I need to determine the voltage drop across R4 using the voltage divider rule.
So far, I have determined total resistance to be R = 383Ω, total current I = 0.03A, and I3 = 0.023A.
I think these are correct.
I then get V through R1 and R2 to be 2.97V, therefore V for the rest of the circuit is 9.03V. Then the voltage for AB should be 9.03V.
Then V for R4 and R5 would be V ab (R45/(R45 + R3) = 9.03 x (41/371) = 1V.
I'm not sure if my methods and calculations are correct as this is very confusing :nb)
 
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LR5 said:
I'm not sure if my methods and calculations are correct as this is very confusing :nb)
How would we know if you are correct, as you show no work on getting the resistance? Show ALL the work used in reducing the circuit, step by step.
 

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