Solving Series Question: Determine Convergence/Divergence

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SUMMARY

The series defined by the expression \(\sum_{n=1}^{\infty}\log_{b^n}\left(1+\frac{\sqrt[n]{a}}{n}\right)\) converges. The solution involves transforming the logarithmic expression into a form that separates the terms, leading to the conclusion that the series converges based on the behavior of \(\frac{\sqrt[n]{a}}{n^2\ln b}\) and the negligible contribution of the \(O\left(\frac{a^{\frac{2}{n}}}{n^3\ln b}\right)\) term. This analysis confirms the convergence of the series for parameters \(a, b > 0\).

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  • Understanding of series convergence tests
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  • Knowledge of asymptotic notation (Big O notation)
  • Basic calculus, particularly limits and sequences
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  • Study the Ratio Test for series convergence
  • Learn about the properties of logarithms in series
  • Explore asymptotic analysis in more depth
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Homework Statement


Determine whether the series converges or diverges.

[tex]\sum_{n=1}^{\infty}\log_{b^n}\left(1+\frac{\sqrt[n]{a}}{n}\right)[/tex]
where a,b>0 some parameters.

The Attempt at a Solution



[tex]\sum_{n=1}^{\infty}\frac{\ln \left(1+\frac{\sqrt[n]{a}}{n}\right)}{\ln b^n }=\sum_{n=1}^{\infty}\frac{\left(\frac{\sqrt[n]{a}}{n}-O\left(\frac{a^{\frac{2}{n}}}{n^2}\right)\right)}{n\ln b}}[/tex]

[tex]=\sum_{n=1}^{\infty}\frac{\sqrt[n]{a}}{n^2\ln b}-\sum_{n=1}^{\infty}O\left(\frac{a^{\frac{2}{n}}}{n^3\ln b}\right)[/tex]

So my solution is series converges.
 
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Thats how I would do it as well =]
 
Thank you!
 

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