Solving Sliding Blocks Down an Inclined Surface

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Two blocks are sliding down an incline, with one block having a wooden surface with a coefficient of friction and the other being frictionless due to a Teflon coating. The larger block has a mass of 4M, while the smaller block has a mass of M. The acceleration of the blocks can be calculated using the formula F=ma, specifically applying the frictional force for the larger block. The proposed solution involves the expression ((4M)(uk)(g)cos(θ))/(4M+M) to determine the acceleration. It is suggested that the blocks may be moving independently down the slope.
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Homework Statement



Two blocks are sliding down an inclide of an angle θ. The larger block has a wooden surface, with a coefficient of friction of uk. The smaller block M is coasted with Teflon, making frictionless contact with the surface. The mass of the larger block is 4M, and the mass of the smaller block is M. Find the acceleration of the blocks.

Homework Equations



F=ma

The Attempt at a Solution



((4M)(uk)(g)cos(θ))/(4M+M)

uk=coefficient of friction

Is this correct?
 
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Dylan6866 said:

Homework Statement



Two blocks are sliding down an inclide of an angle θ. The larger block has a wooden surface, with a coefficient of friction of uk. The smaller block M is coasted with Teflon, making frictionless contact with the surface. The mass of the larger block is 4M, and the mass of the smaller block is M. Find the acceleration of the blocks.

Homework Equations



F=ma

The Attempt at a Solution



((4M)(uk)(g)cos(θ))/(4M+M)

uk=coefficient of friction

Is this correct?

I suspect that the question wants you to assume that the blocks are moving independently down the slope.
 
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