Solving Slingshot Problem Homework

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Homework Help Overview

The discussion revolves around a problem involving a slingshot, focusing on concepts of elastic potential energy, kinetic energy, and efficiency. Participants are examining the relationships between tension forces, measurements of rubber band extension, and energy calculations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to determine the length of tension forces and how they relate to the overall force exerted by the slingshot. Questions arise regarding the measurement of the rubber band and the interpretation of energy values, particularly the discrepancy between calculated and provided energy inputs.

Discussion Status

There is an ongoing exploration of the measurements and calculations involved in the problem. Some participants are questioning the assumptions made about the tension forces and the energy values, while others are clarifying their understanding of vector addition in the context of forces.

Contextual Notes

Participants note potential discrepancies in measurements and the numbering of exercises, which may affect their understanding of the problem. There is also mention of a solution that seems to conflict with their calculations, highlighting areas of confusion that remain unresolved.

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Homework Statement


slingshot question.png

slingshot annex.JPG

Homework Equations



Elastic potential energy = 1/2 * C * u^2

Ek = 1/2 * m * v^2

Efficiency = useful output/total input

The Attempt at a Solution



a) My main problem is to find the length of tension force. From the graph i can see that 12 cm corresponds to 100N, so i just need to find the length of the tension in cm and i can determine it in Newton. The solution states the tension forces are approximately 5.1cm long but i really can't figure out why, for me it seems they kinda arbitrarily picked a point on the slingshot but this can't be the reason.

b) I got it

c) So if i use the formula for kinetic energy i get: Ek = 1/2 * 26*10^-3 kg * (9.3 ms^-1)^2 = 1.12 J.
But i don't know how to calculate the total energy input for the efficiency in this question. The solution says its 7.2J but i thought it should be the 6.0J from b)I hope someone can explain it to me, thanks for every answer.
 

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The meaning of 'extension' of the rubber band is given in the text. Its direction is not along the length of the band but along the direction of the force !
Krashy said:
The solution states the tension forces are approximately 5.1cm long
That would really surprise me: tension forces do not have a length.

What surprises me about your picture is that both halves of the rubber band have 8.5 cm. On my screen I measure 9.5 and 10.5 cm, a considerable difference! Did you take the picture at an angle ?
Anyway, the two halves of the band combined exert 100 N. Your task is to decompose that in two tension forces along the two sections of the band. Do you know how to do that ?

I find it confusing that your exercises are numbered 7, 8, 9, and your answers are 'lettered' a), b), c).

Re c) : apparently you have a solution (manual?) at hand. How come it does not help you to undertand part b) ?

I have no idea where the 7.2 J could come from.
 
Thanks for your reply,
i thought i measured correctly but I am not sure. The 7,8,9 was a mistake in the problem, they are equivalent to a), b), c). Here are the solutions:

solutions.png


But if they have a combined force 100N, then the tension force of one side needs to be 50N, right?
 

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Krashy said:
then the tension force of one side needs to be 50N
Forces are vectors. Do you know how to add vectors ?

I still don't see why the 6J in b) magically changes to 7.2 j in c). Must be an oversight.
 
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Yeah i think i know that, but if each side is 8.5cm long and 9cm = 100N, than one side of 8.5cm = 94N, right? Sorry this problem really confuses me. Do i need to mirror the 9cm on the other side and use trigonometry to solve for the middle side between the other 2 sides?
 
Nevermind, i got it thank you very much for your help!
 

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