Solving Spherical Symmetry in Hydrogen Atom

  • Thread starter Thread starter rubertoda
  • Start date Start date
  • Tags Tags
    Spherical Symmetry
Click For Summary

Homework Help Overview

The discussion revolves around demonstrating spherical symmetry in the hydrogen atom, specifically focusing on the sum of the squares of the spherical harmonics for the l=1 shell. Participants are exploring how this sum should yield a result that is either a constant or zero, indicating no angular dependence.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to calculate the sum of the squares of the spherical harmonics |Y10|^2 + |Y11|^2 + |Y1-1|^2 and are encountering difficulties in simplifying the resulting expressions to a constant or zero. There are questions about the correctness of their approach and the handling of complex numbers in the calculations.

Discussion Status

Some participants are providing guidance on the calculation process, suggesting that the modulus of each term should be taken into account properly. There is an ongoing exploration of the mathematical steps involved, with no explicit consensus reached yet.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the amount of direct assistance they can receive. There are also indications of confusion regarding the treatment of complex numbers in the context of the problem.

rubertoda
Messages
33
Reaction score
0
I have a problem; I am trying to show the spherical symmetry in a hydrogen atom, for a sum over the l=1 shell i.e the sum over the quadratics over three angular wave equations in l=1,

|Y10|^2 + |Y11|^2 + |Y1-1.|^2 .

This should equal up to a constant or a zero to yield no angular dependence. m goes from -l to l.
The problem is that when trying to do this, i get all kinds o different sin, cos formulas, which i cannot reduce to zero or a constant to make the total equation only radial dependent - or am i doing this the wrong way?Anyone who did this problem?
 
Last edited:
Physics news on Phys.org
rubertoda said:
I have a problem; I am trying to show the spherical symmetry in a hydrogen atom, for a sum over the l=1 shell i.e the sum over the quadratics over three angular wave equations in l=1,

|Y10|^2 + |Y11|^2 + |Y1-1.|^2 .

This should equal up to a constant or a zero to yield no angular dependence. m goes from -l to l.



The problem is that when trying to do this, i get all kinds o different sin, cos formulas, which i cannot reduce to zero or a constant to make the total equation only radial dependent - or am i doing this the wrong way?


Anyone who did this problem?

It sounds like you have the correct approach. Why don't you show us your calculation so we can tell you where you are going wrong.
 
gabbagabbahey said:
It sounds like you have the correct approach. Why don't you show us your calculation so we can tell you where you are going wrong.

I have: [tex]|\frac{1}{2}\sqrt{3/2\pi}\sin\theta e^{-i\delta}|^2+|\frac{1}{2}\sqrt{3/2\pi}\sin\theta e^{i\delta}|^2 + |\frac{1}{2}\sqrt{3/\pi}\cos\theta|^2[/tex]

which i finally got to: [tex]\frac{3}{4\pi}((\cos\theta)^2 + (\sin\theta)^2((\cos\delta)^2 - (\sin\delta)^2)[/tex]

which i obviously cannot get to a constant or zero.
 
rubertoda said:
I have: [tex]|\frac{1}{2}\sqrt{3/2\pi}\sin\theta e^{-i\delta}|^2+|\frac{1}{2}\sqrt{3/2\pi}\sin\theta e^{i\delta}|^2 + |\frac{1}{2}\sqrt{3/\pi}\cos\theta|^2[/tex]

which i finally got to: [tex]\frac{3}{4\pi}((\cos\theta)^2 + (\sin\theta)^2((\cos\delta)^2 - (\sin\delta)^2)[/tex]

which i obviously cannot get to a constant or zero.

The deltas should disappear when you take the modulus of each term. For a complex number, the modulus is defined as [itex]|z|=\sqrt{zz^*}[/itex], you don't just square the number, you multiply by its complex-conjugate.
 

Similar threads

  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
29
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
0
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K