Solving Static Structure: Find Forces in B & C

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SUMMARY

The discussion focuses on calculating the forces in structural members B and C using static equilibrium equations. The user attempted to solve the equations \(\sum M_A = BL + 2CL - F \cdot \frac{3}{2}L = 0\) and \(\sum F_Y = B + C - F = 0\) but did not arrive at the correct values of B = 3F/10 and C = 6F/10. A participant pointed out that point C is free floating, indicating that no force is developed at that point, which clarifies the user's confusion.

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The attachment shows a structure. I'm supposed to calculate the forces in the members B and C. I try the following:

[tex] \sum M _A = BL + 2CL - F \cdot {3 \over 2}L = 0[/tex]

[tex] \sum {F_Y = B + C - F = 0} [/tex]

Solving for B and C from this doesn't yield the correct answer, which is B=3F/10 and C=6F/10.

Can someone explain?
 

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Please post homework problems in the homework help section.

As for your problem, it looks as if point C is free floating. So there is no force developed at C. Hope that solves your worries.
 

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