Solving Statics Question: Ty/Tx = 0.18/0.24

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SUMMARY

The discussion centers on solving a statics problem involving a bracket BCD, which is hinged at point C and connected to a control cable at point B. The key equation presented is Ty/Tx = 0.18/0.24, which represents the relationship between the vertical and horizontal components of tension in the cable. This ratio simplifies the analysis by allowing all forces acting on the crank mechanism to be resolved along the x or y-axes, facilitating the calculation of the tension in the cable and the reaction at point C.

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Homework Statement


The Bracket BCD Is hinged at C and attached to a control cable at B. For the loading showm, determine the tension in the cable, the reaction at C.

so after attempting this problem for about an hour and still not getting the right
answer I decided to look up the solution. Only to be more confused can someone
explain why they start the solution off with Ty/Tx = 0.18/0.24 ??
How does setting up this ratio correlate to Ty and Tx?
de0mdc.png
 
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David Donald said:

Homework Statement


The Bracket BCD Is hinged at C and attached to a control cable at B. For the loading showm, determine the tension in the cable, the reaction at C.

so after attempting this problem for about an hour and still not getting the right
answer I decided to look up the solution. Only to be more confused can someone
explain why they start the solution off with Ty/Tx = 0.18/0.24 ??
How does setting up this ratio correlate to Ty and Tx?
de0mdc.png
Ty/Tx = 0.18/0.24 is the relationship between the two components of the tension in the line AB. By using this relationship, all of the forces acting on the crank mechanism are now acting parallel either to the x or y-axes.
 

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