Solving Stress Concentration for Elliptical Hole in Square Panel

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SUMMARY

The discussion focuses on calculating stress concentration factors for an elliptical hole in a square panel subjected to uniform pressure. The parameters specified include a panel length of 40 inches, pressure of 10 psi, elliptical hole dimensions of a=1 inch and b=0.5 inches, and a thickness of 0.2 inches. The stress concentration factor (Kt) is proposed to be calculated using the formula Kt = stress x (1 + 2b/a), with a clarification that the conventional formula is typically 1 + 2(a/b). The relationship indicates that as the width decreases or the length increases, the stress concentration factor increases.

PREREQUISITES
  • Understanding of stress concentration factors in materials
  • Familiarity with basic mechanics of materials
  • Knowledge of elliptical geometry and its application in engineering
  • Experience with pressure loading scenarios in structural analysis
NEXT STEPS
  • Research "Stress Concentration Factors for Elliptical Holes" in engineering literature
  • Study "Finite Element Analysis (FEA) for Stress Distribution" using software like ANSYS
  • Explore "Mechanics of Materials" textbooks for detailed equations and examples
  • Investigate "Crack Propagation Models" in relation to stress concentration
USEFUL FOR

Mechanical engineers, structural analysts, and students studying material mechanics who are involved in stress analysis and design optimization of structural components.

raunakm
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Homework Statement



Square panel , elliptical hole, uniform pressure p in x direction. calc stress at end of minor axis. pt A

L=40in p=10psi a=1in b=0.5 in t=0.2 in

Homework Equations



i know that stress at end will be max stress multiplied by stress conc. factor.
bt i don't know how to calc stress conc. factor for an elliptical hole

The Attempt at a Solution



Kt = stress x (1 + 2b/a)

is this correct?
 

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Can't read the diagram but it's normally 1+2(a/b) where a is the length and b is the width.
So as the width gets smaller or the length is longer - the concentration gets bigger!

Alternatively it's sqrt(crack_length/radius)
 

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