Solving Summations of n.n! Terms

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Homework Help Overview

The discussion revolves around the summation of terms in the form of n.n! for n terms, exploring the properties of the series and the nature of its components.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to analyze the series by identifying the first part of each term as an arithmetic progression and expanding the nth term. Some participants question the utility of substituting n with (n+1)-1 and seek further clarification on this approach.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the substitution of terms, but clarity on its effectiveness remains elusive.

Contextual Notes

Participants are grappling with the implications of the substitution and its relevance to the summation, indicating a potential gap in understanding the series' structure.

utkarshakash
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Homework Statement


1.1!+2.2!+3.3!...n terms

Homework Equations



The Attempt at a Solution


The first part of every term is in AP whose cd is 1. Also the nth term of this series is given as n.n! If I expand it it becomes n.n(n-1)(n-2)...1

Now
S_n=\sum t_n \\<br /> = \sum n.n(n-1)(n-2)...1

But now how do I compute this summation?
 
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Consider n = (n+1)-1
 
Mentallic said:
Consider n = (n+1)-1

I didn't get you. What you said was to replace all the n's with (n+1)-1 but I didn't find it to be helpful. Can you please give me some more hints?
 
utkarshakash said:
I didn't get you. What you said was to replace all the n's with (n+1)-1 but I didn't find it to be helpful. Can you please give me some more hints?

Not all n's!

n.n! = [(n+1)-1]n!
 

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