Solving system of differential equations using matrix exponential

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 1K views
member 731016
Homework Statement
Please see below
Relevant Equations
Please see below
For this problem,
1715474953990.png

The solution is,
1715475028077.png

However, can someone please explain to me where they got the orange coefficient matrix from?It seems different to the original system of the form ##\vec x' = A\vec x## which is confusing me.

Thanks!
 

Attachments

  • 1715474985077.png
    1715474985077.png
    14.4 KB · Views: 133
on Phys.org
This is all about transforming the original matrix A into it's Jordan normal form as the easy way to solve ##e^{At}## (the state transition matrix). But then you have to do the inverse transformation to get it back to the original basis. The reason you find the eigenvectors is to create the Jordan form, which, for simple systems is just a matrix with the e-values on the diagonal.

So, in your case the transform to the Jordan normal form uses the e-vector matrix ##H=
\begin{bmatrix}
1 & 2\\
1 & 1
\end{bmatrix}##
What is it's inverse ##H^{-1}## and how would you use it?

https://math24.net/method-matrix-exponential.html
https://sites.millersville.edu/bikenaga/linear-algebra/matrix-exponential/matrix-exponential.html

plus soooo many other versions of this problem on the web.
 
Reply
  • Love
Likes   Reactions: member 731016
Thank you for your replies @DaveE!

Do you please know why ##Φ'(t) = e^{At}Φ(0)## where ##Φ## is fundamental matrix?

Thanks!